Find out why 10 ÷ 3 and 1 ÷ 7 never end, meet the magic number 142857, and see which fractions give ending decimals.
Preview · progress not saved — Chapter 1 is free
10 ÷ 3 leaves a remainder of 1 at every step.
Watch the remainders go round in a circle.
Problem. Divide 1 by 7. Does it end? (Textbook p. 85)
Decide whether each division ends and what repeats.
The repeating block of 1 ÷ 7 does tricks when multiplied.
Take 142857, the repeating block of . Multiply it by 1, 2, 3, 4, 5 and 6. What do you notice?
142857 × 1 to 7, and the surprise at 7.
Problem. Multiply 142857 by 1, 2, 3, 4, 5, 6 and then 7. (Textbook p. 86)
Emil Artin's 1927 guess is still open today.
Quick questions on 142857.