Bisect any angle using SSS congruence, and use repeated bisection to build 45° designs like the eight-petalled flower.
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Make OA = OB and CA = CB, and OC bisects the angle.
The 8-petalled flower (Fig. 6.5) needs 8 support lines with equal angles between them: . 45° is half of 90°, so we need to bisect an angle.
Build 90°, then bisect it.
Problem. Construct a 45° angle with a ruler and compass. (Textbook p. 144)
Three steps and the reason.
Which angles can we make, and why?
Which of these can be made from 90° and 60° by bisecting (and adding)? (Textbook p. 144, Q4)
The 8-petalled flower and the petals in a square, for the next task.
The 8-petalled flower (Fig. 6.5, Textbook p. 144)
Construct the 8-petalled flower and the petals in a square.
Figure it Out, Textbook p. 144, Q1, Q2 and Q6.
Start from 90°.
Which points of the square do the arcs pass through?
Invent a rope method to bisect an angle.
Figure it Out, Textbook p. 144, Q5. Come up with a method to construct the angle bisector using a rope. Explain why it works.
How do you get equal distances on both arms?
Which congruence condition?